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0.2033g of an organic compound in Dumas ...

`0.2033g` of an organic compound in Dumas method gave `31.7mL` of moist `N_(2)` at `14^(@)C` and `758mm` pressure. Percentage of `N_(2)` in the compound is (Aq.tension at `14^(@)C=14mm)`

Text Solution

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Pressure due to nitrogen only `=758-14=744mm`
Volume of nitrogen at NTP `=(744 xx 31.7 xx 273)/(287 xx 760)`
=29.52mL
Mole of nitrogen `=(29.52)/(22400)`
Weight of nitrogen `(N_(2))= (29.52)/(22400) xx 28= 0.0369g`
% of nitrogen `=(0.0369)/(0.2033) xx 100`= 18.16%
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