0.1890g of an organic compound gave 0.2870g of silver chloride by Carius method. Find the percentage of chlorine in the compound

Answer

To find the percentage of chlorine in the organic compound, we can follow these steps:

### Step 1: Identify the given data
- Mass of organic compound (m) = 0.1890 g
- Mass of silver chloride (AgCl) = 0.2870 g

### Step 2: Determine the atomic mass of chlorine (Cl) and the molecular mass of silver chloride (AgCl)
- Atomic mass of chlorine (Cl) = 35.5 g/mol
- Atomic mass of silver (Ag) = 107.87 g/mol
- Molecular mass of AgCl = Atomic mass of Ag + Atomic mass of Cl
\[ \text{Molecular mass of AgCl} = 107.87 + 35.5 = 143.37 \text{ g/mol} \]

### Step 3: Use the formula to calculate the percentage of chlorine
The formula to find the percentage of chlorine in the organic compound using the Carius method is:
\[ \text{Percentage of Cl} = \left( \frac{\text{Atomic mass of Cl}}{\text{Molecular mass of AgCl}} \right) \times \left( \frac{\text{Mass of AgCl}}{\text{Mass of organic compound}} \right) \times 100 \]

### Step 4: Substitute the values into the formula
\[ \text{Percentage of Cl} = \left( \frac{35.5}{143.37} \right) \times \left( \frac{0.2870}{0.1890} \right) \times 100 \]

### Step 5: Calculate the values
1. Calculate the fraction of atomic mass of Cl to molecular mass of AgCl:
\[ \frac{35.5}{143.37} \approx 0.247 \]
2. Calculate the fraction of mass of AgCl to mass of the organic compound:
\[ \frac{0.2870}{0.1890} \approx 1.519 \]
3. Now multiply these results and then by 100:
\[ \text{Percentage of Cl} \approx 0.247 \times 1.519 \times 100 \approx 37.5\% \]

### Final Result
The percentage of chlorine in the organic compound is approximately **37.5%**.

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