A mineral contained MgO= 31.88%, `SiO_(2)=63.37% and H_(2)O=4.75%`. Show that the simplest formula for the mineral is `H_(2)Mg_(3)Si_(4)O_(12)`. (H=1, Mg=24, Si=28, O=16)

Explanation

To determine the simplest formula for the mineral containing MgO, SiO₂, and H₂O, we will follow these steps:

### Step 1: Calculate the moles of each component

1. **Moles of MgO**:
- Given mass of MgO = 31.88 g
- Molar mass of MgO = 24 (Mg) + 16 (O) = 40 g/mol
- Moles of MgO = Mass / Molar mass = 31.88 g / 40 g/mol = 0.797 moles (approximately 0.8 moles)
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