0.220g of a sample of a volatile compound, containing carbon, hydrogen and chlorine yielded on combustion in oxygen 0.195g of `CO_(2)`, 0.0804g of `H_(2)O`. 0.120g of the compound occupied a volume of 37.24mL at `105^(@)C` and 768mm Hg pressure. Calculate the molecular formula of the compound.

Explanation

To determine the molecular formula of the volatile compound containing carbon, hydrogen, and chlorine, we will follow these steps:

### Step 1: Calculate moles of Carbon from CO2
1. **Find the moles of CO2 produced:**
- Molar mass of CO2 = 12.01 (C) + 2 × 16.00 (O) = 44.01 g/mol
- Moles of CO2 = mass of CO2 / molar mass of CO2
- Moles of CO2 = 0.195 g / 44.01 g/mol = 0.00443 mol

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