An organic compound (A) contains 69.42% C, 5.78% H and 11.57% N. Its vapour density is 60.5. It evolves ammonia when boiled with caustic potash. On heating with `P_(2)O_(5)`, it gives a compound (B) containing 81.55%C, 4.85% H and 13.59% N. On reduction with Na and alcohol, (B) forms a base which reacts with `HNO_(3)` giving off nitrogen and yielding and alcohol (C ). The alcohol can be oxidised to benzoic acid. Assign structural formulae to (A) , (B) and (C )

Explanation

To solve the problem step by step, we will determine the empirical and molecular formulas for the compounds A, B, and C based on the given data and reactions.

### Step 1: Calculate the Empirical Formula of Compound A

1. **Given Percentages**:
- Carbon (C): 69.42%
- Hydrogen (H): 5.78%
- Nitrogen (N): 11.57%
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