A boron-hydrogen compound weighing 0.0553g created a pressure of 0.658 atm in a bulb of 40.7mL volume at `100^(@)C`. Analysis showed it to be 85.7% boron. What is its molecular formula?

Explanation

To find the molecular formula of the boron-hydrogen compound, we will follow these steps:

### Step 1: Use the Ideal Gas Law to find the number of moles (n)
The Ideal Gas Law is given by the equation:
\[ PV = nRT \]

Where:
- \( P \) = pressure in atm (0.658 atm)
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