448mL of a hydrocarbon (A) having C (87.80%), H (12.19%) weight 1.64g at NTP. On hydrogenation it gives 2 methyl pentane. Treatment of (A) with acidic `HgSO_(4)` gives a new compound (B) of molecular weight `C_(6)H_(12)O`. Compound (A) does not react with ammoniacal `AgNO_(3)`. What is the structure of (A)?

Explanation

To determine the structure of the hydrocarbon (A), we will follow a systematic approach based on the information provided in the question.

### Step-by-Step Solution:

1. **Determine the Molar Mass of the Hydrocarbon (A)**:
- Given: Volume of hydrocarbon (A) = 448 mL at NTP.
- At NTP, 1 mole of gas occupies 22400 mL.
- Number of moles of (A) = Volume / Molar Volume = 448 mL / 22400 mL/mol = 0.02 moles.
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