An organic compound, (A) containing C, H, N and O, on analysis gives 49.32% carbon, 9.59% hydrogen and 19.18% nitrogen. (A) on boiling with NaOH gives off `NH_(3)` and a salt which on acidification gives a monobasic nitrogen -free acid (B). The silver salt of (B) contains 59.67% silver. Deduce the structures of (A) and (B)

Explanation

To solve the problem, we will follow a systematic approach to determine the structures of the organic compounds (A) and (B) based on the given data.

### Step 1: Determine the percentage of oxygen in compound (A)
Given the percentages of carbon, hydrogen, and nitrogen:
- Carbon (C) = 49.32%
- Hydrogen (H) = 9.59%
- Nitrogen (N) = 19.18%

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