Calculate the reduction potential for the following half cells at `25^@C`
`Pt|Fe^(2+) (0.1M)-Fe^(3+) (0.01M), E_(Fe^(3+),Fe^(2+))^@=+0.77V`

Explanation

To calculate the reduction potential for the given half cell at 25°C, we will follow these steps:

### Step 1: Identify the half-reaction
The half-reaction provided is:
\[ \text{Fe}^{2+} \rightarrow \text{Fe}^{3+} + e^- \]

This indicates that iron (II) is being oxidized to iron (III), which means it is losing an electron.

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