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0.4bar(23) is equivalent to the fraction...

`0.4bar(23)` is equivalent to the fraction :

A

`(491)/(990)`

B

`(419)/(990)`

C

`(49)/(99)`

D

`(94)/(99)`

Text Solution

AI Generated Solution

The correct Answer is:
To convert the repeating decimal \(0.4\overline{23}\) into a fraction, we can follow these steps: ### Step 1: Define the repeating decimal Let \( x = 0.4\overline{23} \). ### Step 2: Eliminate the repeating part To eliminate the repeating part, we can multiply \( x \) by a power of 10 that moves the decimal point to the right, so the repeating part aligns. Since "23" has two digits, we multiply by 100: \[ 100x = 42.3\overline{23} \] ### Step 3: Set up another equation Next, we multiply \( x \) by 10 to shift the decimal point one place to the right: \[ 10x = 4.23\overline{23} \] ### Step 4: Subtract the two equations Now we have two equations: 1. \( 100x = 42.3\overline{23} \) 2. \( 10x = 4.23\overline{23} \) Subtract the second equation from the first: \[ 100x - 10x = 42.3\overline{23} - 4.23\overline{23} \] This simplifies to: \[ 90x = 42.3 - 4.23 \] ### Step 5: Calculate the right-hand side Now, calculate \( 42.3 - 4.23 \): \[ 42.3 - 4.23 = 38.07 \] So we have: \[ 90x = 38.07 \] ### Step 6: Solve for \( x \) Now, divide both sides by 90: \[ x = \frac{38.07}{90} \] ### Step 7: Convert the decimal to a fraction To convert \( 38.07 \) into a fraction, we can express it as: \[ 38.07 = \frac{3807}{100} \] Thus, we have: \[ x = \frac{3807}{100 \times 90} = \frac{3807}{9000} \] ### Step 8: Simplify the fraction Now we simplify \( \frac{3807}{9000} \). We can find the greatest common divisor (GCD) of 3807 and 9000, which is 3: \[ \frac{3807 \div 3}{9000 \div 3} = \frac{1269}{3000} \] ### Step 9: Final simplification We can check if \( \frac{1269}{3000} \) can be simplified further. The GCD of 1269 and 3000 is 3: \[ \frac{1269 \div 3}{3000 \div 3} = \frac{423}{1000} \] Thus, the final answer is: \[ x = \frac{423}{1000} \] ### Final Answer: The fraction equivalent to \( 0.4\overline{23} \) is \( \frac{423}{1000} \). ---
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ADVANCED MATHS BY ABHINAY MATHS ENGLISH-NUMBER SYSTEM -MULTIPLE CHOICE QUESTIONS
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  2. The least number among (4)/(9), sqrt((9)/(49)) 0.45 and (0.8)^(2) is

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  3. 0.4bar(23) is equivalent to the fraction :

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  4. The value of (0.bar(63) + 0.bar(37)) is

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  5. The difference of 5.bar(76) and 2.bar(3) is

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  6. The decimal fraction 2.3bar(49) is equal to

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  7. Which of the following numbers is the greatest of all? 0.9 ,0.bar(9),...

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  8. 1.bar(27) in the form (p)/(q) is equal to

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  9. A number when divided by 899 gives a remainder 63. If the same number ...

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  10. A number when divided by 899 gives a remainder 63. If the same number ...

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  11. When a number is successively divided by 4 and 5. The remainder obtain...

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  12. When two numbers are separately divided by 33, the remainders are 21 a...

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  13. A number when divided by 3 leaves a remainder 1. When the quotient ...

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  14. A number divided by 13 leaves a remainder 1 and if the quotient, th...

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  15. (7^(19)+2) is divided by 6. The remainder is 1 (b) 2 (c) 3 (d) 5

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  16. Zero' is

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  17. One' is

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  18. Find irrational number between 2 and 3.

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  19. When 'n' is divisible by 5 the remainder is 2. What is the remainder w...

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  20. (49^(13) - 1) is exactly divisible by

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