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Calculate the moment of inertia of a cyl...

Calculate the moment of inertia of a cylinder of length 2 m, radius 5 cm and density `8 xx 10^(3) kg//m^3` about (i) the axis of the cylinder and (ii) and axis passing through the centre and perpendicular to its length.

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To solve the problem of calculating the moment of inertia of a cylinder, we will follow these steps: ### Given Data: - Length of the cylinder, \( L = 2 \, \text{m} \) - Radius of the cylinder, \( r = 5 \, \text{cm} = 0.05 \, \text{m} \) - Density of the cylinder, \( \rho = 8 \times 10^3 \, \text{kg/m}^3 \) ### Step 1: Calculate the Volume of the Cylinder The volume \( V \) of a cylinder is given by the formula: \[ V = \pi r^2 h \] Substituting the values: \[ V = \pi (0.05)^2 (2) = \pi (0.0025)(2) = 0.005\pi \, \text{m}^3 \] ### Step 2: Calculate the Mass of the Cylinder The mass \( m \) can be calculated using the formula: \[ m = \rho V \] Substituting the values: \[ m = 8 \times 10^3 \times 0.005\pi \approx 125.6 \, \text{kg} \] ### Step 3: Calculate the Moment of Inertia about the Axis of the Cylinder (I1) The moment of inertia \( I_1 \) of a solid cylinder about its own axis is given by: \[ I_1 = \frac{1}{2} m r^2 \] Substituting the values: \[ I_1 = \frac{1}{2} \times 125.6 \times (0.05)^2 = \frac{1}{2} \times 125.6 \times 0.0025 \] Calculating: \[ I_1 = \frac{1}{2} \times 125.6 \times 0.0025 \approx 0.157 \, \text{kg m}^2 \] ### Step 4: Calculate the Moment of Inertia about an Axis Perpendicular to its Length (I2) The moment of inertia \( I_2 \) about an axis passing through the center and perpendicular to its length is given by: \[ I_2 = \frac{1}{12} m L^2 + \frac{1}{4} m r^2 \] Substituting the values: \[ I_2 = \frac{1}{12} \times 125.6 \times (2)^2 + \frac{1}{4} \times 125.6 \times (0.05)^2 \] Calculating each term: \[ I_2 = \frac{1}{12} \times 125.6 \times 4 + \frac{1}{4} \times 125.6 \times 0.0025 \] \[ I_2 = \frac{1}{12} \times 502.4 + \frac{1}{4} \times 0.314 \] Calculating: \[ I_2 = 41.8667 + 0.0785 \approx 41.94 \, \text{kg m}^2 \] ### Final Results: 1. Moment of inertia about the axis of the cylinder, \( I_1 \approx 0.157 \, \text{kg m}^2 \) 2. Moment of inertia about the axis perpendicular to its length, \( I_2 \approx 41.94 \, \text{kg m}^2 \)

To solve the problem of calculating the moment of inertia of a cylinder, we will follow these steps: ### Given Data: - Length of the cylinder, \( L = 2 \, \text{m} \) - Radius of the cylinder, \( r = 5 \, \text{cm} = 0.05 \, \text{m} \) - Density of the cylinder, \( \rho = 8 \times 10^3 \, \text{kg/m}^3 \) ### Step 1: Calculate the Volume of the Cylinder ...
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