When a constant torque is applied to a flywheel at rest it angular velocity increases by 10 rad/s in 2 s: Calculate the torque applied if the moment of inertia of the flywheel about the axis of rotation is `200 kg m^(2)`.

Explanation

`a=(omega-omega_(0))t = 10-0//2 = 5 "rads"^(-2), tau = I alpha = 200 xx 5 = 1000 Nm`