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Simplify: (9+4i) ((3)/(2)-i) (9-4i)...

Simplify: `(9+4i) ((3)/(2)-i) (9-4i)`

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To simplify the expression \((9 + 4i) \left(\frac{3}{2} - i\right) (9 - 4i)\), we will follow these steps: ### Step 1: Identify the components We have three parts to multiply: \(9 + 4i\), \(\frac{3}{2} - i\), and \(9 - 4i\). ### Step 2: Use the identity for multiplying conjugates Notice that \( (9 + 4i)(9 - 4i) \) is a product of conjugates. We can use the identity: \[ (a + b)(a - b) = a^2 - b^2 \] Here, \(a = 9\) and \(b = 4i\). ### Step 3: Calculate \( (9 + 4i)(9 - 4i) \) Using the identity: \[ (9 + 4i)(9 - 4i) = 9^2 - (4i)^2 \] Calculating each term: \[ 9^2 = 81 \quad \text{and} \quad (4i)^2 = 16i^2 = 16(-1) = -16 \] Thus, we have: \[ 81 - (-16) = 81 + 16 = 97 \] ### Step 4: Multiply by \(\left(\frac{3}{2} - i\right)\) Now we need to multiply the result \(97\) by \(\left(\frac{3}{2} - i\right)\): \[ 97 \left(\frac{3}{2} - i\right) \] Distributing \(97\): \[ = 97 \cdot \frac{3}{2} - 97i \] ### Step 5: Calculate \(97 \cdot \frac{3}{2}\) Calculating the multiplication: \[ 97 \cdot \frac{3}{2} = \frac{291}{2} \] ### Step 6: Combine the results Putting it all together, we have: \[ \frac{291}{2} - 97i \] ### Final Answer Thus, the simplified form of the expression \((9 + 4i) \left(\frac{3}{2} - i\right) (9 - 4i)\) is: \[ \frac{291}{2} - 97i \] ---
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ICSE-COMPLEX NUMBERS-Exercise (B)
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