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Find 12th term of a G.P. whose 8th term ...

Find 12th term of a G.P. whose 8th term is 192 and the common ratio is 2.

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To find the 12th term of a geometric progression (G.P.) given that the 8th term is 192 and the common ratio is 2, we can follow these steps: ### Step 1: Understand the formula for the nth term of a G.P. The nth term of a G.P. can be expressed as: \[ a_n = a \cdot r^{n-1} \] where: - \( a \) is the first term, - \( r \) is the common ratio, - \( n \) is the term number. ### Step 2: Write the equation for the 8th term. Given that the 8th term \( a_8 = 192 \): \[ a_8 = a \cdot r^{8-1} = a \cdot r^7 \] Substituting the known values: \[ a \cdot 2^7 = 192 \] ### Step 3: Calculate \( 2^7 \). Calculate \( 2^7 \): \[ 2^7 = 128 \] ### Step 4: Substitute \( 2^7 \) into the equation. Now substitute \( 128 \) into the equation: \[ a \cdot 128 = 192 \] ### Step 5: Solve for \( a \). To find \( a \), divide both sides by \( 128 \): \[ a = \frac{192}{128} = \frac{3}{2} \] ### Step 6: Write the equation for the 12th term. Now we need to find the 12th term \( a_{12} \): \[ a_{12} = a \cdot r^{12-1} = a \cdot r^{11} \] Substituting the values of \( a \) and \( r \): \[ a_{12} = \frac{3}{2} \cdot 2^{11} \] ### Step 7: Calculate \( 2^{11} \). Calculate \( 2^{11} \): \[ 2^{11} = 2048 \] ### Step 8: Substitute \( 2^{11} \) into the equation for \( a_{12} \). Now substitute \( 2048 \) into the equation: \[ a_{12} = \frac{3}{2} \cdot 2048 \] ### Step 9: Simplify to find \( a_{12} \). Calculating \( a_{12} \): \[ a_{12} = \frac{3 \cdot 2048}{2} = \frac{6144}{2} = 3072 \] ### Final Answer: The 12th term of the G.P. is \( 3072 \). ---
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ICSE-SEQUENCE AND SERIES -CHAPTER TEST
  1. If the first term of an A.P. is 2 and the sum of first five terms is e...

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  2. Insert 3 arithmetic means between 2 and 10.

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  3. Find 12th term of a G.P. whose 8th term is 192 and the common ratio is...

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  4. The first term of a G.P. is 1. The sum of the third and fifth terms is...

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  5. The sum of first three terms of a G.P. is (39)/(10) and their product ...

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  6. The sum of some terms of a G.P. is 315 whose first term and the common...

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  7. Find the sum of the series 0.6 +0.66 +0.666+ ... to the n terms

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  8. The sum of an infinite series is 15 and the sum of the squares of thes...

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  9. Insert three geometric means between 1 and 256.

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  10. In the sum to infinity of the series 3+(3+x) (1)/(4) + (3+2x)(1)/(4^(2...

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  11. Find the sum to n terms of the series 3.8 +6.11 +9.14 + ...

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  12. Find the sum 5^(2)+ 6^(2) + 7^(2) + ... + 20^(2).

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  13. If in a geometric progression consisting of positive terms, each term ...

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  14. If the first term of an infinite G.P. is 1 and each term is twice the ...

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  15. If fifth term of a G.P. is 2, then the product of its first 9 terms is

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  16. The sum of three decreasing numbers in A.P. is 27. If-1,-1, 3 are adde...

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  17. The first two terms of a geometric progression add up to 12. The sum o...

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  18. The sum to infinity of the series 1+2/3+6/3^2+14/3^4+...is

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  19. The sum of all odd numbers between 1 and 100 which are divisible by 3,...

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  20. If a, b, c are in G.P. and x, y are arithmetic means of a, b and b, c ...

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