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The sum of three decreasing numbers in A...

The sum of three decreasing numbers in A.P. is 27. If-1,-1, 3 are added to them respectively, the resulting series is in G.P. The numbers are

A

5,9,13

B

15,9,3

C

13,9,5

D

17,9,1

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The correct Answer is:
To solve the problem, we need to find three decreasing numbers in Arithmetic Progression (A.P.) whose sum is 27. Additionally, when we add -1, -1, and 3 to these numbers respectively, the resulting numbers form a Geometric Progression (G.P.). ### Step-by-Step Solution: 1. **Define the A.P. Terms:** Let the three numbers in A.P. be: - First term: \( a + d \) - Second term: \( a \) - Third term: \( a - d \) 2. **Set Up the Equation for the Sum:** According to the problem, the sum of these three terms is 27: \[ (a + d) + a + (a - d) = 27 \] Simplifying this, we have: \[ 3a = 27 \] Therefore, we find: \[ a = 9 \] 3. **Substitute \( a \) Back into the A.P. Terms:** Now substituting \( a = 9 \) into the terms, we have: - First term: \( 9 + d \) - Second term: \( 9 \) - Third term: \( 9 - d \) 4. **Add the Given Values to the A.P. Terms:** According to the problem, we add -1, -1, and 3 to the terms respectively: - First term becomes: \( (9 + d) - 1 = 8 + d \) - Second term becomes: \( 9 - 1 = 8 \) - Third term becomes: \( (9 - d) + 3 = 12 - d \) 5. **Set Up the G.P. Condition:** The three resulting terms \( 8 + d, 8, 12 - d \) must be in G.P. For three numbers to be in G.P., the square of the middle term must equal the product of the other two terms: \[ 8^2 = (8 + d)(12 - d) \] This simplifies to: \[ 64 = (8 + d)(12 - d) \] 6. **Expand and Rearrange the Equation:** Expanding the right side: \[ 64 = 96 - 8d + 12d - d^2 \] Rearranging gives: \[ d^2 - 4d - 32 = 0 \] 7. **Solve the Quadratic Equation:** We can factor this quadratic: \[ (d - 8)(d + 4) = 0 \] Thus, the solutions for \( d \) are: \[ d = 8 \quad \text{or} \quad d = -4 \] 8. **Find the A.P. Terms for Each \( d \):** - If \( d = 8 \): - The terms are \( 9 + 8 = 17, 9, 9 - 8 = 1 \) (which are decreasing). - If \( d = -4 \): - The terms are \( 9 - 4 = 5, 9, 9 + 4 = 13 \) (which are increasing). 9. **Conclusion:** Since we need decreasing numbers, the valid solution is: \[ 17, 9, 1 \] ### Final Answer: The three decreasing numbers in A.P. are **17, 9, and 1**.
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ICSE-SEQUENCE AND SERIES -CHAPTER TEST
  1. If the first term of an A.P. is 2 and the sum of first five terms is e...

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  2. Insert 3 arithmetic means between 2 and 10.

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  3. Find 12th term of a G.P. whose 8th term is 192 and the common ratio is...

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  4. The first term of a G.P. is 1. The sum of the third and fifth terms is...

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  5. The sum of first three terms of a G.P. is (39)/(10) and their product ...

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  6. The sum of some terms of a G.P. is 315 whose first term and the common...

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  7. Find the sum of the series 0.6 +0.66 +0.666+ ... to the n terms

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  8. The sum of an infinite series is 15 and the sum of the squares of thes...

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  9. Insert three geometric means between 1 and 256.

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  10. In the sum to infinity of the series 3+(3+x) (1)/(4) + (3+2x)(1)/(4^(2...

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  11. Find the sum to n terms of the series 3.8 +6.11 +9.14 + ...

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  12. Find the sum 5^(2)+ 6^(2) + 7^(2) + ... + 20^(2).

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  13. If in a geometric progression consisting of positive terms, each term ...

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  14. If the first term of an infinite G.P. is 1 and each term is twice the ...

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  15. If fifth term of a G.P. is 2, then the product of its first 9 terms is

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  16. The sum of three decreasing numbers in A.P. is 27. If-1,-1, 3 are adde...

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  17. The first two terms of a geometric progression add up to 12. The sum o...

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  18. The sum to infinity of the series 1+2/3+6/3^2+14/3^4+...is

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  19. The sum of all odd numbers between 1 and 100 which are divisible by 3,...

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  20. If a, b, c are in G.P. and x, y are arithmetic means of a, b and b, c ...

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