Calculate the normality of a solution of `FeSO_(4).7H_(2)O` containing 2.4g/100 mL (Fe=56,S=32,O=16,H=1) which converts to ferric form in a reaction .

Explanation

To calculate the normality of a solution of `FeSO4.7H2O` containing 2.4 g per 100 mL that converts to ferric form, we can follow these steps:

### Step 1: Calculate the Molecular Weight of `FeSO4.7H2O`

The molecular weight of `FeSO4.7H2O` can be calculated using the atomic weights provided:

- Iron (Fe) = 56 g/mol
- Sulfur (S) = 32 g/mol
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