What is the strength in grams/litre of a solution of `H_(2)SO_(4)` ,12 c c of which neutralises 15 c c of `N/10` NaOH solution ?

Explanation

To find the strength in grams per liter of a solution of \( H_2SO_4 \) that neutralizes a given volume of \( N/10 \) NaOH solution, we can follow these steps:

### Step 1: Understand the neutralization reaction
The reaction between sulfuric acid (\( H_2SO_4 \)) and sodium hydroxide (\( NaOH \)) can be represented as:
\[ H_2SO_4 + 2NaOH \rightarrow Na_2SO_4 + 2H_2O \]
From this equation, we see that 1 mole of \( H_2SO_4 \) reacts with 2 moles of \( NaOH \).
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