In a quantitative determination of iron in an ore, an analyst converted `0.42` g of the ore into its ferrous form . This required `42.00` mL of `0.1` N solution of `KMnO_(4)` for titration.
How many milliequivalents of `KMnO_(4)` does `42.00` mL of `0.1 ` N solution represent ?

Explanation

In this problem `Fe^(2+)` is oxidised to `Fe^(3+)` by `KMnO_(4)`
(i) m.e of `KMnO_(4)` solution =`0.1 xx42 =4.2 " " ….(Eqn 1)`