One gram - atom of Ca burnt in excess of oxygen was dissolved in water to make up a litre solution. Calculate the normality alkaline solution .

Explanation

First Method
`Ca (O_(2))/(" burnt") CaO (" disolved in water ") to Ca(OH)_(2)`
m.e of Ca = m.e of CaO = m.e of 1000 mL of `Ca(OH)_(2)` solution
` :. ` m.e of 1000 mL of `Ca(OH)_(2)` solution = m.e of Ca
` = eq xx 1000`
= (gram - atom ` xx` valency of Ca) `xx` 1000
` = 1 xx 2 xx 1000`
= 2000
` :. `normality of `Ca(OH)_(2)` solution = `(m.e)/(" vol in mL")`
` (2000)/(1000 ) = 2 N `