Mercuric iodate `[Hg_(5)(IO_(6))_(2)]` reacts with a mixture of KI and HCI according to the following equation .
`Hg_(5)(IO_(6))_(2) +34 KI +24 HCl to 5K_(2)HgI_(4) +8I_(2) +24KCl +12H_(2)O `
The liberated odine is treated with `na_(2)S_(2)O_(3)` solution , 1 mL of which is equivalent to `0.0499` g of `CuSO_(4).5H_(2)O ` .What volume( in mL ) of `Na_(2)S_(2)O_(3)` solution will be required to react with iodine liberated from `0.7245` g of `[Hg_(5) (IO_(6))_(2)]` ? [Hg = 200.5 , Cu = 63.5 ,I = 127 ]

Mercuric iodate [Hg_5(IO_6)_2] reacts with a mixutre of KI and HCl according to the following equation. Hg_5(IO_6)_2+34KI+24"HCl"to5K_2HgI_4+8I_2+24KCI+12H_2O or Hg_5(IO_6)_2+34I^(ɵ)+24H^(o+)to5HgI_4^(2-)+8I_2+12H_2O The liberated I_2 is titrated with Na_2S_2O_3 solution. 1.0 " mL of " Na_2S_2O_3 is equivalent to 3.992 g of CuSO_4.5H_2O . What volume (in mL) of the Na_2S_2O_3 solution will be required to react with liberated I_2 from 14.485 g Hg_5(IO_6)_2 . [Hg=200.5,Cu=63.5,I=127] ? Mw(Hg_5(IO_6)_2)=1448.5g Mw(CuSO_4.5H_2O)=249.5g

Calculate the formality of sodium thiosulphate (Na_(2)S_(2)O_(3).5H_(2)O) solution , 1.24 g of which are dissolved in 100 cm^(3) of the solution.

80 mL of M/24 K_(2)Cr_(2)O_(7) oxidises 22.4 mL H_(2)O_(2) solution. Find volume strength of H_(2)O_(2) solution.

Oxalic acid, H_(2)C_(2)O_(4) , reacts with paramagnet ion according to the balanced equation 5H_(2)C_(2)O_(4)(aq)+2MnO_(4)^(-)hArr2Mn^(2+)(aq)+10CO_(2)(g)+8H_(2)O(l) . The volume in mL of 0.0162 M KMnO_(4) solution required to react with 25.0 mL of 0.022 M H_(2)C_(2)O_(4) solution is :