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A 250-mL sample of 0.20 M hydrochloric ...

A 250-mL sample of `0.20` M hydrochloric acid to be made by diluting the approximate amount of the concentrated reagent `11.7` M .What volume of the latter should be used ?

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To solve the problem of determining the volume of concentrated hydrochloric acid (HCl) needed to prepare a 250 mL solution of 0.20 M HCl from an 11.7 M concentrated solution, we can use the dilution formula: **Step 1: Identify the known values.** - Molarity of the diluted solution (M1) = 0.20 M - Volume of the diluted solution (V1) = 250 mL = 0.250 L (convert mL to L by dividing by 1000) - Molarity of the concentrated solution (M2) = 11.7 M - Volume of the concentrated solution (V2) = ? (this is what we need to find) ...
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