How many mL of concentrated suphuric acid of sp. Gr `1.84` containing 98 % `H_(2)SO_(4)` solution by weight is required to prepare 200 mL of `0.5` N solution ?

Explanation

To solve the problem, we need to determine how many mL of concentrated sulfuric acid (H₂SO₄) is required to prepare 200 mL of a 0.5 N solution. Here’s a step-by-step breakdown of the solution:

### Step 1: Calculate the number of equivalents needed
Normality (N) is defined as the number of equivalents of solute per liter of solution. For sulfuric acid (H₂SO₄), which can donate two protons (H⁺), the equivalent weight is half its molar mass.

1. **Calculate the equivalents needed for 200 mL of 0.5 N solution:**
\[
\text{Equivalents} = \text{Normality} \times \text{Volume (L)} = 0.5 \, \text{N} \times 0.2 \, \text{L} = 0.1 \, \text{equivalents}
...