A mixture of KMnO(4) and K(2)Cr(2)O(7) w...

A mixture of `KMnO_(4) and K_(2)Cr_(2)O_(7)` weighing `0.24` g on being treated with KI in acid solution liberates just sufficient `I_(2)` to react with 60 mL of `0.1` N `Ha_(2)S_(2)O_(3)` solution . Calculate percentage of Cr and Mn in the mixture .

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The correct Answer is:

`20.83% , 14.17%`

`underset(+7) (KMnO_(4)) to underset(+2) (Mn^(2+))and underset(+12)(K_(2)Cr_(2)O_(7))to underset(+6)(2Cr^(3+)]`

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