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In a conductivity cell the two platinum ...

In a conductivity cell the two platinum electrodes each of area 10 sq. cm are fixed 1.5 cm apart. The cell. Contained `0.05N` solution of a salt. If the two electrodes are just half dipped into the solution which has a resistance of 50 ohms, find equivalent conductance of the salt solution.

Text Solution

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Since the electroces of the cell are just half dipped, the effective area will be 5 sq cm.
Cell constant `= (1)/(a) = (1.5)/(5) = 0.3 cm^(-1)`.
Specific conductance = conductance `xx` cell constant
`= (1)/("resistance") xx "cell constant"`
`= (1)/(50) xx 0.3 = (3)/(500) = "mho cm"^(-1)`.
Equivalent conductance = specific conductance `xx` volume
`= (3)/(500) xx 20000 = 120 "mho cm"^(2)`.
`(0.05 N = N//20 therefore V = 20,000 c c)`
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