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A 0.01 D^(**) solution of KCl has a spec...

A 0.01 `D^(**)` solution of KCl has a specific conductance value of 0.00141 mho `cm^(-1)`. A cell filled with this solution has a resistance of 42156 ohms.
(a) What is the cell constant ?
(b) The same cell filled with a solution of Hcl has a resistance of 1.0326 ohms. What is specific conductivity of the HCl solution ?

Text Solution

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(a) Cell constant `= ("specific conductance")/("conductance")`
`= ("specific conductance")/("1/resistance")`
`= (0.00141)/(1//4.2156) = 0.00594 cm^(-1)`.
(b) Conductance of Hcl solution `= (1)/(1.0326)` mho.
Sicne the same cell is used, we shall take the same value of cell constant in this case.
Sp. conductance = cell constant `xx` conductance
`= 0.00594 xx (1)/(1.0326)`
`= 0.00575 "mho cm"^(-1)`.
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