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The equivalent conductance of an infinit...

The equivalent conductance of an infinitely dilute solution of `NH_(4)Cl` is 150 and te ionic conductance of `OH^(-)` ad `Cl^(-)` ions are 198 and 76 respectively. What will be the equivalent conductance of the solution of `NH_(4)OH` at infinite dilution. if the equivalent conductance of a 0.01 N solution `NH_(4)OH` is 9.6, what will be its degree of dissociation?

Text Solution

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`Lambda_(NH_(4)Cl)^(@) = lambda_(NH_(4)^(+))^(@) + lambda_(Cl^(-))^(@)`
`therefore lambda_(NH_(4)^(+))^(@) = Lambda_(NH_(4)Cl)^(@) - lambda_(Cl^(-))^(@) = 150 - 76 = 74`
`therefore Lambda_(NH_(4)OH)^(@) = lambda_(NH_(4)^(+))^(@) + lambda_(OH^(-))^(@) = 74 + 198 = 272`
Further,
degree of dissociation `= (Lambda_(c))/(Lambda^(@))`
`= (9.6)/(272) = 0.0353`
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