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Calculate K(a) of acetic acif if its 0.0...

Calculate `K_(a)` of acetic acif if its 0.05 N solution has equivalent conductance of 7.36 mho `cm^(2)` at `25^(@)C`. `" " (Lambda_(CH_(3)COOH)^(@) = 290.7)`

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To calculate the dissociation constant \( K_a \) of acetic acid from the given data, we can follow these steps: ### Step 1: Understand the given data We are given: - Normality of acetic acid solution, \( N = 0.05 \, \text{N} \) - Equivalent conductance, \( \Lambda = 7.36 \, \text{mho} \, \text{cm}^2 \) - Conductivity of acetic acid, \( \Lambda_{CH_3COOH} = 290.7 \, \text{mho} \, \text{cm}^2 \) ...
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