Ag is electrodeposited on a metallic vessel of surface area `800 cm^(2)` by passing a current of 0.2 amp for three hours. Calculate the thickness of silver deposited, given its density is 10.47 g/cc.

Explanation

To solve the problem of calculating the thickness of silver deposited on a metallic vessel, we can follow these steps:

### Step 1: Calculate the total charge passed
First, we need to calculate the total charge (Q) passed through the solution. The formula for charge is given by:
\[ Q = I \times t \]
where:
- \( I \) = current in amperes (0.2 A)
- \( t \) = time in seconds
...