50 mL of a 0.1 M `CuSO_(4)` solution is electrolysed for 12 minutes at a current of 0.06 amp. If Cu is produced at one electrode and `O_(2)` at the other, what will be the pH of the final solution ? For `HSO_(4)^(-) = H^(+) + SO_(4)^(2-), K_("diss") = 1.3 xx 10^(-2)`

Answer

2.95