Home
Class 12
CHEMISTRY
A solution containing Cu(I), Ni and Zn c...

A solution containing Cu(I), Ni and Zn cyanide complexes was electrolysed and a deposit of 0.175 g was obtained. The deposit contained 72.8% Cu, 4.3% Ni and 22.9% Zn. No other element was released. Calculate the number of coulombs passed through the solution.

Text Solution

AI Generated Solution

The correct Answer is:
To calculate the number of coulombs passed through the solution during the electrolysis, we will follow these steps: ### Step 1: Calculate the mass of each metal in the deposit The total mass of the deposit is 0.175 g. We will calculate the mass of Cu, Ni, and Zn based on their percentage composition. - Mass of Cu = 72.8% of 0.175 g - Mass of Ni = 4.3% of 0.175 g - Mass of Zn = 22.9% of 0.175 g Calculating these values: - Mass of Cu = 0.728 * 0.175 g = 0.1234 g - Mass of Ni = 0.043 * 0.175 g = 0.007525 g - Mass of Zn = 0.229 * 0.175 g = 0.040075 g ### Step 2: Calculate the number of moles of each metal Using the molar masses: - Molar mass of Cu = 63.5 g/mol - Molar mass of Ni = 58.7 g/mol - Molar mass of Zn = 65.4 g/mol Calculating the number of moles: - Moles of Cu = Mass of Cu / Molar mass of Cu = 0.1234 g / 63.5 g/mol = 0.001943 mol - Moles of Ni = Mass of Ni / Molar mass of Ni = 0.007525 g / 58.7 g/mol = 0.000128 mol - Moles of Zn = Mass of Zn / Molar mass of Zn = 0.040075 g / 65.4 g/mol = 0.000613 mol ### Step 3: Calculate the total charge for each metal Now we will calculate the total charge using Faraday's laws of electrolysis. The number of electrons transferred for each metal is as follows: - Cu (Cu^+): 1 electron - Ni (Ni^2+): 2 electrons - Zn (Zn^2+): 2 electrons Calculating the total charge (Q) for each metal: - Charge for Cu = Moles of Cu × 1 × 96500 C/mol = 0.001943 mol × 1 × 96500 C/mol = 187.4 C - Charge for Ni = Moles of Ni × 2 × 96500 C/mol = 0.000128 mol × 2 × 96500 C/mol = 24.7 C - Charge for Zn = Moles of Zn × 2 × 96500 C/mol = 0.000613 mol × 2 × 96500 C/mol = 118.5 C ### Step 4: Calculate the total charge passed through the solution Now, we will sum the charges for Cu, Ni, and Zn to find the total charge passed through the solution: Total Charge (Q_total) = Charge for Cu + Charge for Ni + Charge for Zn Q_total = 187.4 C + 24.7 C + 118.5 C = 330.6 C ### Final Answer The total number of coulombs passed through the solution is approximately **330.6 C**. ---
Promotional Banner

Topper's Solved these Questions

  • ELECTROLYSIS AND ELECTROLYTIC CONDUCTANCE

    RC MUKHERJEE|Exercise Objective Problems|39 Videos
  • ELECTROLYSIS AND ELECTROLYTIC CONDUCTANCE

    RC MUKHERJEE|Exercise Examples On Conductance|13 Videos
  • DILUTE SOLUTION AND COLLIGATIVE PROPERTIES

    RC MUKHERJEE|Exercise Objective problems|36 Videos
  • ELECTROMOTIVE FORCE

    RC MUKHERJEE|Exercise EXERCISE |1 Videos

Similar Questions

Explore conceptually related problems

An acidic solution of Cu^(2+0 salt containing 0.4g of Cu^(2+) is electrolyzed until all the copper is deposited. The electrolysis is continued for seven more minutes with the volume of solution kept at 100mL and the current at 1.2A . Calculate the volume of gases evolved at STP during the entire electrolysis.

A current of 2A was passed for 1.5 hours through a solution of CuSO_(4) when 1.6g of copper was deposited. Calculate percentage current efficiency.

An acidic solution of Cu^(2+) ions containing 0.4 g of Cu^(2+) ions is electrolysed until all the copper is deposited. Calculate the valume of oxygen evolved at N.T.P.

RC MUKHERJEE-ELECTROLYSIS AND ELECTROLYTIC CONDUCTANCE-Problems
  1. 40 mL of 0.125 M of NiSO(4) solution is electrolysed by a current of 0...

    Text Solution

    |

  2. An electric current is passed through a solution of (i) silver nitrate...

    Text Solution

    |

  3. In a fuel cell, hydrogen and oxygen react to produce electricity. In p...

    Text Solution

    |

  4. 3A current was passed through an aqueous solution of an unknown salt o...

    Text Solution

    |

  5. A total of 69500 C of electricity was required to reduced 37.7 g of M^...

    Text Solution

    |

  6. A solution containing Cu(I), Ni and Zn cyanide complexes was electroly...

    Text Solution

    |

  7. Calculate the minimum number of kWh of electricity required to produce...

    Text Solution

    |

  8. A sample of Al(2)O(3) dissolved in a molten fluoride bath is electroly...

    Text Solution

    |

  9. The specific conductance of a N//10 KCI solution at 18^(@)C is 1.12 xx...

    Text Solution

    |

  10. When a solution of conductance 1.342 mho "metre"^(-1) was placed in a ...

    Text Solution

    |

  11. The resistance of two electrolytes X and Y ere found to be 45 and 100 ...

    Text Solution

    |

  12. The resistance of an aqueous solution containing 0.624g of CuSO(4).5H(...

    Text Solution

    |

  13. An aqueous solution of 0.02 M KCl solution is filled in a 25-cm-long c...

    Text Solution

    |

  14. Given the equivalent conductance of sodium butyrate sodium chloride an...

    Text Solution

    |

  15. A dilute aqueous solution of KCI was placed between two electrodes 10 ...

    Text Solution

    |

  16. For 0.0128 N solution fo acetic at 25^(@)C equivalent conductance of t...

    Text Solution

    |

  17. The specific conductance at 25^(@)C of a saturated solution of AgCl in...

    Text Solution

    |

  18. Specific conductance of pure water at 25^(@)C is 0.58 xx 10^(-7) mho c...

    Text Solution

    |

  19. The molar conductivity of a solution of a weak acid HX(0.01 M) is 10 t...

    Text Solution

    |

  20. The conductance of a 0.0015 M aqueous solution of a weak monobasic aci...

    Text Solution

    |