An aqueous solution of 0.02 M KCl solution is filled in a 25-cm-long capillary tube of internal radius 0.01 cm. The solution was found to have a specific conductance of `0.0027 "mho cm"^(-1)`. What will be the current in amp when a potential of 2 volts is appled across the capillary tube ?

Explanation

To solve the problem step by step, we will use the information provided and apply the relevant formulas.

### Step 1: Identify the given values
- Concentration of KCl solution (C) = 0.02 M
- Length of the capillary tube (L) = 25 cm = 0.25 m
- Internal radius of the capillary tube (r) = 0.01 cm = 0.0001 m
- Specific conductance (κ) = 0.0027 mho/cm = 0.0027 S/m (since 1 mho/cm = 10 S/m)
- Potential difference (V) = 2 V
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