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A mixture of H(2) and O(2) in 2:1 volume...

A mixture of `H_(2) and O_(2)` in `2:1` volume is allowed to diffuse through a porous partition what is the composition of gas coming out initially

Text Solution

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We have,
`(r_(H_(2)))/(r_(O_(2))) = sqrt((M_(O_(2)))/(M_(H_(2)))) = sqrt((32)/(2)) = 4`.
Now since volum ratio of `H_(2)` and `O_(2)` in the initial stage is 2 :1 (given) and the ratio of there ratio is 4:1, the overall volume ratio of the gases diffusing through the porous partition at the initial stage will be 8:1.
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