Express the results of the following calculations to the appropriate number of significant figures.
(i) `(3.24 xx 0.08666)/(5.006)`, (ii) `0.58 + 324.65`
(iii) `943 xx 0.00345 + 101`

Explanation

(i) In this calculation, the least precise number, i.e., 3.24 has three significant figures. Therefore, the result should be reported upto three significant figures only. Hence,
`(3.24 xx 0.08666)/(5.006) = 0.0560883 = 0.0561`
(ii) In this calculation, both the numbers have two decimal places. Hence, the result should be reported upto two decimal places only. Therefore, `0.58 + 324.65 = 325.23` Ans.
(iii) In this calculation 943 and 101 are exact numbers. An exact number is supposed to have infinite number of significant figures.
Therefore, the least precise number is 0.00345 which consists of three significant figures. Therefore, `943 xx 0.00345 + 101 = (3.25335) + 101 = 3.25 + 101 = 104.25`
It is to be noted that the product of numbers 943 and 0.00345 comes out to be 3.25335. The result to be reported should contain three significant figures. Therefore, it should be written in the form 3.25. This number now contains two decimal places. Therefore, the result obtained after addition of 101 to it should also have two decimal places. Therefore, the final answer is 104.25.