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In an experiment 5.0 g of CaCO(3) on hea...

In an experiment 5.0 g of `CaCO_(3)` on heating gave 2.8 g of CaO and 2.2 g of `CO_(2)`. Show that these results are in accordance to the law of conservation of mass.

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Calcium carbonate decomposes on heating according to the following equation.
`underset(5 g)(CaCO_(3)) to underset(2.9 g)(CaO) + underset(2.2 g)(CO_(2))`
The total mass of reactant (`CaCO_3`) taken at the beginning of the reaction = 5 g.
The total mass of products (`CaO + CO_2`) obtained
`=2.8 + 2.2 = 5.0 g`
Since, the total mass of the products obtained in the reaction is the same as that of the reactant taken, the results are in accordance to the law of conservation of mass.
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