How many molecules of water of crystallisation are present in 1.648 g of copper sulphate `(CuSO_(4).5H_(2)O)` ?

Explanation

To find the number of molecules of water of crystallization present in 1.648 g of copper sulfate pentahydrate (CuSO₄·5H₂O), we can follow these steps:

### Step 1: Calculate the molar mass of CuSO₄·5H₂O
The molar mass of CuSO₄·5H₂O can be calculated by adding the molar masses of its components:
- Molar mass of Cu (Copper) = 63.55 g/mol
- Molar mass of S (Sulfur) = 32.07 g/mol
- Molar mass of O (Oxygen) in CuSO₄ = 4 × 16.00 g/mol = 64.00 g/mol
- Molar mass of H₂O (Water) = 2 × 1.01 g/mol + 16.00 g/mol = 18.02 g/mol
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