A sample of nitric acid is 55 per cent by mass. Calculate the mass of nitric acid present in `100 cm^(3)`of the sample if its density is `1.36 g cm^(-3)`.

Explanation

Since, the given sample is 55% by mass, 100 g of the sample would contain 55 g of `HNO_3`.
Since, density `=("mass")/("volume")`
Therefore, the volume of 100 g of the sample `=("mass")/("density") = 100/(1.36) = 73.5 cm^(3)`
Thus,73.5 cm of the given sample contains 55 g of `HNO_3`.
Hence, the mass of `HNO_3` present in 100 cm of the sample
`=55/(73.5) xx 100 = 74.8 g`