A solution is prepared by dissolving 0.63 g of oxalic acid in `100 cm^(3)` of water. Find the normality of the solution.

Explanation

To find the normality of the solution prepared by dissolving 0.63 g of oxalic acid in 100 cm³ of water, we can follow these steps:

### Step 1: Determine the molecular mass of oxalic acid
The molecular formula of oxalic acid is \( C_2H_2O_4 \). The molecular mass can be calculated as follows:
- Carbon (C): \( 2 \times 12 \, \text{g/mol} = 24 \, \text{g/mol} \)
- Hydrogen (H): \( 2 \times 1 \, \text{g/mol} = 2 \, \text{g/mol} \)
- Oxygen (O): \( 4 \times 16 \, \text{g/mol} = 64 \, \text{g/mol} \)

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