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A sample of zinc oxide contains 80.25% z...

A sample of zinc oxide contains 80.25% zinc. Calculate the equivalent mass of zinc.

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To calculate the equivalent mass of zinc in a sample of zinc oxide that contains 80.25% zinc, we can follow these steps: ### Step 1: Define the mass of zinc oxide Let the total mass of the zinc oxide (ZnO) sample be \( X \) grams. ### Step 2: Calculate the mass of zinc Since the sample contains 80.25% zinc, the mass of zinc (Zn) in the sample can be calculated as: \[ \text{Mass of Zn} = \frac{80.25}{100} \times X = 0.8025X \] ### Step 3: Calculate the mass of oxygen in zinc oxide The remaining percentage of the sample is oxygen. Therefore, the mass of oxygen (O) in the sample can be calculated as: \[ \text{Mass of O} = \frac{100 - 80.25}{100} \times X = \frac{19.75}{100} \times X = 0.1975X \] ### Step 4: Calculate the equivalent mass of zinc The equivalent mass of zinc can be calculated using the formula: \[ \text{Equivalent mass of Zn} = \frac{\text{Mass of Zn}}{\text{Mass of O in ZnO}} \times 8 \] Substituting the values we found: \[ \text{Equivalent mass of Zn} = \frac{0.8025X}{0.1975X} \times 8 \] ### Step 5: Simplify the equation The \( X \) cancels out: \[ \text{Equivalent mass of Zn} = \frac{0.8025}{0.1975} \times 8 \] ### Step 6: Calculate the ratio Calculating the ratio: \[ \frac{0.8025}{0.1975} \approx 4.06 \] Now, multiplying by 8: \[ \text{Equivalent mass of Zn} \approx 4.06 \times 8 \approx 32.48 \text{ grams} \] ### Final Result Thus, the equivalent mass of zinc is approximately: \[ \text{Equivalent mass of Zn} \approx 32.51 \text{ grams} \]
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