What is the total number of electrons present in 1.6 g of methane?

Answer

`6.0 xx 10^(23)`

Explanation

The molecular formula of methane is `CH_4`. Since, one atom of carbon contains 6 electrons and one atom of hydrogen contains one electron, one molecule of methane will contain 10 electrons.
The gram molecular mass of methane `=12.01 + (4 xx 1.008) = 16.042 g`
This mass will contain `6.022 xx 10^23` molecules.
Hence, the total number of electrons present in 1.6 g of methane = `6.0 xx 10^(22) xx 10 = 6.0 = 10^(22)`