calculte the total number of electrons present 1.4 g of dinitrogen gas.

Explanation

Moles of `N_2 = (1.4)/28 = 0.05`
No. of molecules present `= 0.05 xx 6.022 xx 10^(23)`
`:. "No. of electrons present " = 0.05 xx 6.022 xx 10^(23) xx 14`
`( :. 1 "molecule of " N_2` contains 14 electrons)
= `4.2154 xx 10^(23)` electrons