Calculate the total pressure in a mixture of 8 g of dioxygen and 4 g of dihydrogen confined in a vessel of 1 `dm^(3)` at `27^(@)C.` R =0.083 bar `dm^(3)K^(-1)mol^(-1).`

Explanation

Total number of moles present in the mixture
`=8/32 + 4/2 = 2.25`
(Mol. mass of `O_2 = 32, " Mol. mass of " H_2 = 2`)
According to the gas equation,
`PV = nRT`
or `P xx 1= 2.25 xx 0.083 xx 300`
or `P= 2.25 xx 0.083 xx 300 = 56.025` bar