With the help of a balanced chemical equation, show that `B(OH)_3` behaves as an acid in water.

Explanation

To show that \( B(OH)_3 \) (boric acid) behaves as an acid in water, we can follow these steps:

### Step 1: Understand the Structure of Boric Acid
Boric acid, \( B(OH)_3 \), consists of a boron atom bonded to three hydroxyl (–OH) groups. It can also be represented as \( H_3BO_3 \).

### Step 2: Write the Reaction of Boric Acid with Water
When boric acid is dissolved in water, it interacts with water molecules. The reaction can be represented as follows:

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