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Which of the following statements is not...

Which of the following statements is not correct for `BF_3` ?

A

It can form adduct

B

It acts as a Lewis base

C

It forms an ionic bond

D

It also forms dative bonds with compounds like `NH_3`, etc.

Text Solution

AI Generated Solution

The correct Answer is:
To determine which statement is not correct for \( BF_3 \), we will analyze each statement based on the properties and behavior of boron trifluoride. ### Step 1: Analyze the structure of \( BF_3 \) - **Boron trifluoride (\( BF_3 \))** consists of a boron atom bonded to three fluorine atoms. - Boron is **sp² hybridized**, which means it has one empty p-orbital and is electron-deficient. ### Step 2: Evaluate the statements 1. **It can form an adduct.** - This statement is correct. \( BF_3 \) can accept an electron pair from a Lewis base (like \( NH_3 \)) to form an adduct. 2. **It acts as a Lewis base.** - This statement is incorrect. \( BF_3 \) is a Lewis acid because it is electron-deficient and can accept electrons, not donate them. 3. **It forms an ionic bond.** - This statement is also incorrect. \( BF_3 \) does not form ionic bonds; it typically forms covalent bonds and coordinate (or dative) bonds with Lewis bases. 4. **It also forms dative bonds with compounds like \( NH_3 \).** - This statement is correct. \( BF_3 \) can form dative bonds with \( NH_3 \) when \( NH_3 \) donates its lone pair to \( BF_3 \). ### Conclusion The statements that are not correct for \( BF_3 \) are: - **It acts as a Lewis base.** - **It forms an ionic bond.** ### Final Answer The statements that are not correct for \( BF_3 \) are: - It acts as a Lewis base. - It forms an ionic bond. ---

To determine which statement is not correct for \( BF_3 \), we will analyze each statement based on the properties and behavior of boron trifluoride. ### Step 1: Analyze the structure of \( BF_3 \) - **Boron trifluoride (\( BF_3 \))** consists of a boron atom bonded to three fluorine atoms. - Boron is **sp² hybridized**, which means it has one empty p-orbital and is electron-deficient. ### Step 2: Evaluate the statements 1. **It can form an adduct.** ...
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