The tendency to form `p_(pi) - p_(pi)` multiple bonds in group 14 is
most prominent for

Options

A. C
B. Si
C. Sn
D. Pb

Explanation

To solve the question regarding the tendency to form \( p_{\pi} - p_{\pi} \) multiple bonds in group 14 elements, we can follow these steps:

### Step 1: Understand the Group 14 Elements
Group 14 of the periodic table consists of elements such as Carbon (C), Silicon (Si), Germanium (Ge), Tin (Sn), and Lead (Pb).

### Step 2: Identify the Concept of \( p_{\pi} - p_{\pi} \) Bonding
The \( p_{\pi} - p_{\pi} \) bonding refers to the overlap of p-orbitals from adjacent atoms to form multiple bonds (like double or triple bonds). This type of bonding is crucial in determining the reactivity and bonding characteristics of the elements.

### Step 3: Analyze the Trend in Group 14
As we move down the group from Carbon to Lead:
- The size of the atoms increases.
- The effectiveness of \( p_{\pi} - p_{\pi} \) bonding decreases due to the larger atomic size and increased distance between the p-orbitals.
- Additionally, larger atoms experience more repulsion between the electrons in the p-orbitals, which further reduces the tendency to form multiple bonds.

### Step 4: Compare the Elements
- **Carbon**: Being the smallest element in the group, it has the highest tendency to form \( p_{\pi} - p_{\pi} \) multiple bonds with other elements (like nitrogen and oxygen).
- **Silicon**: Although it can form some multiple bonds, its larger size and the associated factors reduce this tendency significantly.
- **Germanium, Tin, and Lead**: These elements have even larger atomic sizes, making \( p_{\pi} - p_{\pi} \) bonding even less favorable.

### Step 5: Conclusion
From the analysis, we conclude that the tendency to form \( p_{\pi} - p_{\pi} \) multiple bonds is most prominent for **Carbon** in Group 14.

### Final Answer
The tendency to form \( p_{\pi} - p_{\pi} \) multiple bonds in group 14 is most prominent for **Carbon (C)**.

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