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The compound that decolourises alk. KMnO...

The compound that decolourises alk. `KMnO_4` is

A

`C_3H_8`

B

`C_2H_4`

C

`CH_4`

D

`"CCl"_4`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which compound decolorizes alkaline KMnO4, we need to identify which of the given compounds is unsaturated. Alkaline KMnO4 is a strong oxidizing agent that reacts with unsaturated compounds (those containing double or triple bonds) and causes a color change, typically decolorizing the purple color of KMnO4. ### Step-by-Step Solution: 1. **Identify the Compounds**: The options provided are: - C3H8 (Propane) - C2H4 (Ethylene) - CH4 (Methane) - CCl4 (Carbon Tetrachloride) 2. **Classify the Compounds**: - C3H8 (Propane) is a saturated hydrocarbon (alkane) with no double or triple bonds. - C2H4 (Ethylene) is an unsaturated hydrocarbon (alkene) with a double bond. - CH4 (Methane) is also a saturated hydrocarbon (alkane) with no double or triple bonds. - CCl4 (Carbon Tetrachloride) is a saturated compound and does not contain any double or triple bonds. 3. **Determine Reactivity with KMnO4**: - Since KMnO4 can oxidize unsaturated compounds, we check which of the options is unsaturated. - C3H8, CH4, and CCl4 are all saturated and will not react with KMnO4 to decolorize it. - C2H4, being an unsaturated compound, will react with KMnO4 and cause it to lose its purple color. 4. **Conclusion**: The compound that decolorizes alkaline KMnO4 is C2H4 (Ethylene). ### Final Answer: **C2H4 (Ethylene)** is the compound that decolorizes alkaline KMnO4.
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Knowledge Check

  • Among the following compounds which one cannot decolourise alkaline KMnO_(4) solution?

    A
    `HC-=CH`
    B
    `CH_(3)-CH_(2)-OH`
    C
    `CH_(3)-overset(O)overset(||)C-H`
    D
    `CH_(3)-CH_(3)`

  • A compound decolourises Baeyer's reagent and gives a mixture of propanoic acid and ethanoic acid when treated with a hot and conc. solution of KMnO_4 . The compound is

    A
    pent-1-ene
    B
    pent-2-ene
    C
    2-methylbut-1-ene
    D
    2-methylbut-2-ene

  • An alcohol (A) on dehyration gives (B), which on ozonolysis gives acetone and fromaldehyde. (B) decolourises alkaline KMnO_(4) solution but (A) does not. (A) and (B) are respectively :

    A
    `CH_(3)CH_(2)CH_(2)CH_(2)OHandCH_(3)CH_(2)CH=CH_(2)`
    B
    `CH_(2)CH_(2)-underset(OH)underset(|)(CH)-CH_(3)andCH_(3)-CH=CH-CH_(3)`
    C
    `(CH_(3))_(3)C-OHand(CH_(3))_(2)C=CH_(2)`
    D
    `CH_(3)-CH_(2)-underset(OH)underset(|)(CH)-CH_(3)and(CH_(3))_(2)C=CH_(2)`

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