When a cell is placed in 0.5 M solution of salt and no change in the volume of the cell is observed, the concentration of cell sap would be

Options

A. 0.5 M
B. 0.05 M
C. 5.0 M
D. 50 M

Answer

To solve the question of determining the concentration of cell sap when a cell is placed in a 0.5 M solution of salt and no change in the volume of the cell is observed, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Tonicity**:
- Tonicity refers to the relative concentration of solutes in a solution compared to the concentration of solutes in a cell. There are three types of tonic solutions: isotonic, hypotonic, and hypertonic.
- Isotonic means the concentration of solutes is the same inside and outside the cell, hypotonic means the outside solution has a lower concentration of solutes than inside the cell, and hypertonic means the outside solution has a higher concentration of solutes than inside the cell.

2. **Identify the Given Information**:
- The cell is placed in a 0.5 M salt solution.
- There is no change in the volume of the cell.

3. **Analyze the Implication of No Change in Volume**:
- If there is no change in the volume of the cell when placed in the salt solution, it indicates that the concentration of solutes inside the cell (cell sap) is equal to the concentration of the salt solution outside the cell.
- This means that the cell is in an isotonic environment.

4. **Determine the Concentration of Cell Sap**:
- Since the external solution is 0.5 M and the cell volume remains unchanged, we conclude that the concentration of the cell sap must also be 0.5 M.

5. **Final Answer**:
- Therefore, the concentration of the cell sap is **0.5 M**.