A stone is thrown vertically upwards with an initial velocity of 40 m `s^(-1)`. Taking g = 10 m `s^(-2)`, draw the velocity-time graph of the motion of stone till it comes back on the ground.
(i) Use graph to find the maximum height reached by the stone. (ii) What is the net displacement and total distance covered by the stone ?

Explanation

To solve the problem step by step, let's break it down into parts:

### Step 1: Understanding the Motion
A stone is thrown vertically upwards with an initial velocity of 40 m/s. The acceleration due to gravity (g) is acting downwards at 10 m/s². This means that the stone will rise until its velocity becomes zero, then it will fall back down.

### Step 2: Creating a Velocity-Time Table
We can create a table to track the velocity of the stone at different times until it returns to the ground.

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