A particle starts to move in a straight line from a point with velocity 10 m `s^(-1)` and acceleration - 2.0 `m s^(-2)`. Find the position and velocity of the particle at (i) t = 5 s, (ii) t' = 10 s.

Explanation

To solve the problem, we will use the equations of motion. The initial velocity (u) is 10 m/s, the acceleration (a) is -2 m/s², and we need to find the position (s) and velocity (v) at two different times: t = 5 s and t = 10 s.

### Step-by-Step Solution:

#### Part (i): At t = 5 s

1. **Calculate the Position (s) at t = 5 s:**
We use the second equation of motion:
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