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A train travels with a speed of 60 km h^...

A train travels with a speed of 60 km `h^(-1)`' from station A to station B and then comes back with a speed 80 km `h^(-1)`' from station B to station A. Find : (i) the average speed, and (ii) the average velocity of train.

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To solve the problem, we need to calculate both the average speed and the average velocity of the train. Let's break it down step by step. ### Step 1: Define the distance Let the distance between station A and station B be \( x \) kilometers. ### Step 2: Calculate total distance traveled The train travels from A to B and then back from B to A. Therefore, the total distance traveled by the train is: \[ \text{Total Distance} = x + x = 2x \text{ kilometers} \] ### Step 3: Calculate time taken for each leg of the journey 1. **Time taken to travel from A to B** at a speed of 60 km/h: \[ t_1 = \frac{x}{60} \text{ hours} \] 2. **Time taken to travel from B to A** at a speed of 80 km/h: \[ t_2 = \frac{x}{80} \text{ hours} \] ### Step 4: Calculate total time taken The total time taken for the entire journey is the sum of the time taken for each leg: \[ \text{Total Time} = t_1 + t_2 = \frac{x}{60} + \frac{x}{80} \] To add these fractions, we need a common denominator. The least common multiple of 60 and 80 is 240. \[ t_1 = \frac{x}{60} = \frac{4x}{240}, \quad t_2 = \frac{x}{80} = \frac{3x}{240} \] Now, adding these: \[ \text{Total Time} = \frac{4x}{240} + \frac{3x}{240} = \frac{7x}{240} \text{ hours} \] ### Step 5: Calculate average speed The average speed is given by the formula: \[ \text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}} = \frac{2x}{\frac{7x}{240}} = 2x \times \frac{240}{7x} = \frac{480}{7} \approx 68.57 \text{ km/h} \] ### Step 6: Calculate average velocity Average velocity is defined as: \[ \text{Average Velocity} = \frac{\text{Displacement}}{\text{Total Time}} \] Since the train returns to its starting point (station A), the total displacement is zero: \[ \text{Displacement} = 0 \text{ km} \] Thus, the average velocity is: \[ \text{Average Velocity} = \frac{0}{\text{Total Time}} = 0 \text{ km/h} \] ### Final Answers 1. Average Speed: \( 68.57 \text{ km/h} \) 2. Average Velocity: \( 0 \text{ km/h} \) ---

To solve the problem, we need to calculate both the average speed and the average velocity of the train. Let's break it down step by step. ### Step 1: Define the distance Let the distance between station A and station B be \( x \) kilometers. ### Step 2: Calculate total distance traveled The train travels from A to B and then back from B to A. Therefore, the total distance traveled by the train is: \[ ...
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ICSE-MOTION IN ONE DIMENSION -EXERCISE -2 (C) ( Multiple choice type :)
  1. The correct equation of motion is :

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  2. A car starting from rest accelerates uniformly to acquire a speed 20 k...

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  3. A body starts from rest with a uniform acceleration of 2 m s^(-1) . Fi...

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  4. A body starts with an initial velocity of 10 ms and acceleration 5 ms....

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  5. A vehicle is accelerating on a straight road. Its velocity at any inst...

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  6. A body, initially at rest, starts moving with a constant acceleration ...

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  7. A bullet initially moving with a velocity 20 m s^(-1) strikes a target...

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  8. A train moving with a velocity of 20 m s^(-1)' is brought to rest by a...

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  9. A train travels with a speed of 60 km h^(-1)' from station A to statio...

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  10. A train is moving with a velocity of 90 km h^(-1). It is brought to st...

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  11. A car travels a distance 100 m with a constant acceleration and averag...

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  12. When brakes are applied to a bus, the retardation produced is 25 cm s^...

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  13. A body moves from rest with a uniform acceleration and travels 270 m i...

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  14. A body moving with a constant acceleration travels the distances 3 m a...

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  15. A car travels with a uniform velocity of 25 m s^(-1) for 5 s. The brak...

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  16. A space craft flying in a straight course with a velocity of 75 km s^(...

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  17. A train starts from rest and accelerates uniformly at a rate of 2 m s^...

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