Find the length and perimeter of a rectangle, whose area = 120 `cm^(2)` and breadth = 8 cm.

Answer

To solve the problem of finding the length and perimeter of a rectangle given its area and breadth, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Formula for Area of a Rectangle**:
The area \( A \) of a rectangle is given by the formula:
\[ A = \text{Length} \times \text{Breadth} \]

2. **Substitute the Given Values**:
We know the area \( A = 120 \, \text{cm}^2 \) and the breadth \( B = 8 \, \text{cm} \). We can substitute these values into the area formula:
\[ 120 = \text{Length} \times 8 \]

3. **Solve for Length**:
To find the length \( L \), we can rearrange the equation:
\[ L = \frac{120}{8} \]
Now, perform the division:
\[ L = 15 \, \text{cm} \]

4. **Calculate the Perimeter**:
The perimeter \( P \) of a rectangle is given by the formula:
\[ P = 2 \times (\text{Length} + \text{Breadth}) \]
Substitute the values of length and breadth:
\[ P = 2 \times (15 + 8) \]
Calculate the sum inside the parentheses:
\[ P = 2 \times 23 \]
Now, perform the multiplication:
\[ P = 46 \, \text{cm} \]

### Final Answers:
- Length of the rectangle: \( 15 \, \text{cm} \)
- Perimeter of the rectangle: \( 46 \, \text{cm} \)